جواب:
# r ^ 2 = 4 / (cos ^ 2theta + 4sin ^ 2theta) #
# r = sqrt (4 / (cos ^ 2theta + 4sin ^ 2theta)) = 2 / sqrt (cos ^ 2theta + 4sin ^ 2theta) #
وضاحت:
ہم دو فارمولوں کا استعمال کریں گے:
# x = rcostheta #
# y = rsintheta #
# x ^ 2 = r ^ 2cos ^ 2theta #
# y ^ 2 = r ^ 2sin ^ 2theta #
# r ^ 2cos ^ 2theta + 4r ^ 2sin ^ 2theta = 4 #
# r ^ 2 (cos ^ 2theta + 4sin ^ 2theta) = 4 #
# r ^ 2 = 4 / (cos ^ 2theta + 4sin ^ 2theta) #
# r = sqrt (4 / (cos ^ 2theta + 4sin ^ 2theta)) = 2 / sqrt (cos ^ 2theta + 4sin ^ 2theta) #
